xpliu2022
commented
1 month ago Hi,
We cannot use the full CIR length in Viterbi, because that makes the Viterbi algorithm to be too complex when M is large. So, we only consider L1 in the number of states in Viterbi. You may wonder why the channel length is 5, that is because in Viterbi, we have done track back and used previous decisions to form a full states matrix (see lines 68-78).
From: DoraemonBo @.> Sent: Friday, August 9, 2024 4:03 PM To: xpliu2022/SCBSS @.> Cc: Subscribed @.***> Subject: [xpliu2022/SCBSS] About Channel Length (Issue #2)
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In your code, Channel Length is 2. Is that consequence length? Because your CIR's length is 5. So I think L=L1+L2+1 that L1 is consequence length, and L2 is non-consequence length. L1=L2=2, L=5. But state number should be M^2(L-1)=4096, In your code, it is M^(2L1)=256. So I confused.
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DoraemonBo
In your code, Channel Length is 2. Is that consequence length? Because your CIR's length is 5. So I think L=L1+L2+1 that L1 is consequence length, and L2 is non-consequence length. L1=L2=2, L=5. But state number should be M^2(L-1)=4096, In your code, it is M^(2L1)=256. So I confused.