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2022.03.10-第37题-146. LRU 缓存 #39

Open icodeish opened 2 years ago

icodeish commented 2 years ago

https://leetcode-cn.com/problems/lru-cache/

请你设计并实现一个满足  LRU (最近最少使用) 缓存 约束的数据结构。 实现 LRUCache 类: LRUCache(int capacity) 以 正整数 作为容量 capacity 初始化 LRU 缓存 int get(int key) 如果关键字 key 存在于缓存中,则返回关键字的值,否则返回 -1 。 void put(int key, int value) 如果关键字 key 已经存在,则变更其数据值 value ;如果不存在,则向缓存中插入该组 key-value 。如果插入操作导致关键字数量超过 capacity ,则应该 逐出 最久未使用的关键字。 函数 get 和 put 必须以 O(1) 的平均时间复杂度运行。

 

示例:

输入 ["LRUCache", "put", "put", "get", "put", "get", "put", "get", "get", "get"] [[2], [1, 1], [2, 2], [1], [3, 3], [2], [4, 4], [1], [3], [4]] 输出 [null, null, null, 1, null, -1, null, -1, 3, 4]

icodeish commented 2 years ago
var LRUCache = function (capacity) {
    this.capacity = capacity
    this.map = new Map()
}
LRUCache.prototype.get = function (key) {
    if (this.map.has(key)) {
        let value = this.map.get(key)
        this.map.delete(key)
        this.map.set(key, value)
        return value
    } else {
        return -1
    }
}
LRUCache.prototype.put = function (key, value) {
    if (this.map.has(key)) {
        this.map.delete(key)
    }
    this.map.set(key, value)
    if (this.map.size > this.capacity) {
        this.map.delete(this.map.keys().next().value)
    }
}
BambooSword commented 2 years ago
class LRUCache {
    capacity: number
    map: Map<number, number>
    constructor(capacity: number) {
        this.capacity = capacity;
        this.map = new Map();
    }

    get(key: number): number {
        if (this.map.has(key)) {
            const val = this.map.get(key)
            this.map.delete(key)
            this.map.set(key, val)
            return val;
        }

        return -1;
    }

    put(key: number, value: number): void {
        if(this.map.has(key)) {
            this.map.delete(key);
        }
        this.map.set(key, value);
        if (this.map.size > this.capacity) {
            this.map.delete([...this.map.keys()][0])
        }
    }
}

/**
 * Your LRUCache object will be instantiated and called as such:
 * var obj = new LRUCache(capacity)
 * var param_1 = obj.get(key)
 * obj.put(key,value)
 */
yanggengzhen123 commented 2 years ago
class LRUCache {
    capacity:number
     map: Map<number, number>
    constructor(capacity: number) {
        this.capacity = capacity
        this.map = new Map()
    }

    get(key: number): number {
        if(this.map.has(key)){
            const val = this.map.get(key)
            this.map.delete(key)
            this.map.set(key,val)
            return val
        }
        return -1
    }

    put(key: number, value: number): void {
        if(this.map.has(key)){
            this.map.delete(key)
        }
        this.map.set(key,value)
        if(this.capacity < this.map.size){
            // map.keys()迭代器
            this.map.delete([...this.map.keys()][0])
        }
    }
}