Open icodeish opened 2 years ago
var MinStack = function () {
this.stack = []
this.min_stack = [Infinity]
};
/**
* @param {number} val
* @return {void}
*/
MinStack.prototype.push = function (val) {
this.stack.push(val)
this.min_stack.push(Math.min(this.min_stack[this.min_stack.length - 1], val))
};
/**
* @return {void}
*/
MinStack.prototype.pop = function () {
this.stack.pop()
this.min_stack.pop()
};
/**
* @return {number}
*/
MinStack.prototype.top = function () {
return this.stack[this.stack.length - 1]
};
MinStack.prototype.getMin = function () {
return this.min_stack[this.min_stack.length - 1]
};
class MinStack {
data: number[]
minStack: number[]
len: number
constructor() {
this.data = [];
this.minStack = []
this.len = 0;
}
push(val: number): void {
this.data.push(val);
this.minStack.push(this.len ===0 || val < this.minStack[this.len -1] ? val : this.minStack[this.len -1]);
this.len ++
}
pop(): void {
this.data.pop()
this.minStack.pop()
this.len --;
}
top(): number {
return this.data[this.len -1]
}
getMin(): number {
return this.minStack[this.minStack.length -1];
}
}
/**
* Your MinStack object will be instantiated and called as such:
* var obj = new MinStack()
* obj.push(val)
* obj.pop()
* var param_3 = obj.top()
* var param_4 = obj.getMin()
*/
class MinStack {
stack = []
min_stack = [Infinity];
constructor() {
}
push(val: number): void {
this.stack.push(val)
this.min_stack.push(Math.min(val,this.min_stack[this.min_stack.length - 1]))
}
pop(): void {
this.stack.pop()
this.min_stack.pop()
}
top(): number {
return this.stack[this.stack.length - 1]
}
getMin(): number {
return this.min_stack[this.min_stack.length - 1]
}
}
https://leetcode-cn.com/problems/min-stack/ 设计一个支持 push ,pop ,top 操作,并能在常数时间内检索到最小元素的栈。
实现 MinStack 类:
MinStack() 初始化堆栈对象。 void push(int val) 将元素val推入堆栈。 void pop() 删除堆栈顶部的元素。 int top() 获取堆栈顶部的元素。 int getMin() 获取堆栈中的最小元素。
示例 1:
输入: ["MinStack","push","push","push","getMin","pop","top","getMin"] [[],[-2],[0],[-3],[],[],[],[]]
输出: [null,null,null,null,-3,null,0,-2]
解释: MinStack minStack = new MinStack(); minStack.push(-2); minStack.push(0); minStack.push(-3); minStack.getMin(); --> 返回 -3. minStack.pop(); minStack.top(); --> 返回 0. minStack.getMin(); --> 返回 -2.