Closed GoogleCodeExporter closed 9 years ago
Hi Paul,
Kaneko and Ampuero (2011) used Nadia Lapusta's code, which assumes periodic
boundary conditions and loading by steady slip on a fault section. QDYN also
has an option for periodic boundaries but it is instead loaded by remote
displacements on a boundary parallel to the fault, at a distance W. The
boundary conditions of Kaneko and Ampuero (2011) cannot be exactly reproduced
with QDYN. However, by setting MESHDIM=1 and FINITE=1 you can apply a steady
slip velocity over the semi-infinite region of the fault outside the
rate-and-state region. That might be sufficiently similar.
Also note that Lapusta's code includes complete elastodynamics, but QDYN is
only quasi-dynamic. You should expect some differences in the results due to
that too.
I also found the following errors in your input parameters:
+ the simulations are on a 1D fault embedded in a 2D medium, hence you must set
MESHDIM=1.
+ velocity cut-off was not used, you must set RNS_LAW=0 (sorry this parameter
is not documented in the manual).
Let me know if that helps.
Pablo Ampuero
Original comment by ampu...@caltech.edu
on 11 Apr 2013 at 5:24
Just too clarify I have attached a figure with my understanding of the code
(QDYN_example_2D.jpg). If so, is it possible to formulate the problem as
depicted in the separately attached figure (Possible_formulation.jpg).
Original comment by pa.selva...@gmail.com
on 11 Apr 2013 at 10:56
Attachments:
Sorry I just noticed that this figure was hard to read due to missing dashed
lines.
Original comment by pa.selva...@gmail.com
on 12 Apr 2013 at 1:15
Attachments:
I am afraid there is some confusion there. The boundary condition FINITE=1 is
only implemented for 2D media, but your left figures are 3D. MESHDIM=1 means
that the fault is a one-dimensional line contained in a two-dimensional elastic
medium.
With MESHDIM=1, the parameter NW is ignored, only NX is considered. Slip
parallel to X (mode II) or normal to X (mode III) follow similar equations, if
you set MU=(shear modulus)/(1 - Poisson's ratio) in mode II.
You can think of MESHDIM=1 as the special case of a 3D problem where slip is
invariant along one of the axis, as if fault cells were infinitely elongated in
one direction.
Original comment by ampu...@caltech.edu
on 12 Apr 2013 at 6:00
Sorry for the confusion. It is completely clear now. Thank you kindly. I
removed the figures to avoid further confusion.
Original comment by pa.selva...@gmail.com
on 12 Apr 2013 at 6:27
Original comment by ampu...@caltech.edu
on 2 Nov 2014 at 11:00
Original issue reported on code.google.com by
pa.selva...@gmail.com
on 9 Apr 2013 at 6:06