Closed GoogleCodeExporter closed 8 years ago
The syntax here is a little ambiguous because braces are optional when using
$placeholder.
If you use ${placeholder} around the expression, everything will work correctly.
In this case:
var bar={ cat: ${foo($bar("dog"))} };
Original comment by ms...@gmail.com
on 12 Aug 2009 at 8:17
Original issue reported on code.google.com by
mervyn.y...@gmail.com
on 12 Aug 2009 at 4:54