Closed happysnzy closed 1 year ago
Hi @happysnzy ,
There is no ‘WeisfeilerLehman’ kernel alone. Usually when one speaks about the ‘WeisfeilerLehman’ kernel alone, she refers to the Weisfeiler-Lehman subtree kernel (i.e., 'VertexHistogram' as the base kernel). Therefore, the statement you provided is not correct.
My understanding is that ‘WeisfeilerLehman’ must be used in conjunction with a base graph kernel, such as 'VertexHistogram'. If I want to use graph kernel ‘WeisfeilerLehman’ alone, what should I do? Is the following statement correct? ‘gk = WeisfeilerLehman(n_iter=50, base_graph_kernel=WeisfeilerLehman, normalize=True)’