Open ahmubashshir opened 1 year ago
.search()
engine.search(...)
page=N
[ results[], len(results[]), pagenum, pages ]
Related #687
Implementation
.search()
, if pagination is unsupported, page count will be 1engine.search(...)
is called withpage=N
ti returns paginated result, otherwise it returns an array of first n results (old behavior)[ results[], len(results[]), pagenum, pages ]
Related #687