Computation should not depend on non-unique characters in the alphabet

[jt3k]

now a different result of the calculation if the alphabet "01" and "010"

[zelark]

If an alphabet contains non-unique characters, it's marked by red color. But such alphabet is correct as an input.

The calculator do a computation as long as it can. Thereby the result of the computation is consistent with its inputs.

now a different result of the calculation if the alphabet "01" and "010"

Actually, it will give you the same result but with different distribution of "0".

[jt3k]

All the same I see a mistake, because in the case of '010', the collision will happen no later than c '01', but the calculator tells us that the collision will happen later

[zelark]

but the calculator tells us that the collision will happen later

Oh, that's right. I think I'll fix it soon. Thanks.