两个不同的实例之间会互相干扰

[liaokaime]

当我使用如下代码，5秒钟后，a的播放会停止，a与b属于两个不同的实例，但它们之间却会互相干扰，如何使得它们互相不干扰？

        let a = new Sound(this.url,Sound.MAIN_BUNDLE,(e)=>{
            a.play();
        });

        let b = new Sound(this.url,Sound.MAIN_BUNDLE,(e)=>{
            setTimeout(()=>{b.pause()},5000);
        });

[liaokaime]

当我使用如下代码，5秒钟后，a的播放会停止，a与b属于两个不同的实例，但它们之间却会互相干扰，如何使得它们互相不干扰？

        let a = new Sound(this.url,Sound.MAIN_BUNDLE,(e)=>{
            a.play();
        });

        let b = new Sound(this.url,Sound.MAIN_BUNDLE,(e)=>{
            setTimeout(()=>{b.pause()},5000);
        });

我的试过另一种写法，它们不会互相干扰，为什么？

let a = new Sound(this.url,Sound.MAIN_BUNDLE,(e)=>{
            a.play();
            let b = new Sound(this.url,Sound.MAIN_BUNDLE,(e)=>{
                setTimeout(()=>{b.play()},5000);
            });
        });

[liaokaime]

Anybody know why?

[liaokaime]

如果您需要帮助，请用英文写

When I use the following code, after 5 seconds, the play of a will stop, a and b belong to two different instances, but they will interfere with each other, how to make them do not interfere with each other?

        let a = new Sound(this.url,Sound.MAIN_BUNDLE,(e)=>{
            a.play();
        });

        let b = new Sound(this.url,Sound.MAIN_BUNDLE,(e)=>{
            setTimeout(()=>{b.pause()},5000);
        });

Thank you for your reminding. I used English to describe the problem.