Closed Robinlovelace closed 4 years ago
I imagine n could be the number of quadrants, with multiples of 4 being most sensible I guess. Any ideas of an efficient way to do this @mtennekes ?
Taking a break from this today, catch up tomorrow in Oxford!
I imagine n could be the number of quadrants, with multiples of 4 being most sensible I guess. Any ideas of an efficient way to do this @mtennekes ?