flutterchina / json_model

Generate model class from Json file. 一行命令,通过Json文件生成Dart Model类。
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多个@JsonKey使用,只有最后一个属性输出 #40

Open liubaoxinggo opened 4 years ago

liubaoxinggo commented 4 years ago

` { "Euid": "sample string 1",

"Name": "sample string 2",

"DepartmentId": "sample string 3",

"@JsonKey(ignore: true) String":"Pinyin",

"@JsonKey(ignore: true) String":"firstName",

"@JsonKey(ignore: true) String":"tagIndex" } ` 执行命令后输出如下

`@JsonSerializable() class Employee { Employee();

String Euid;
String Name;
String DepartmentId;
@JsonKey(ignore: true) String tagIndex;

factory Employee.fromJson(Map<String,dynamic> json) => _$EmployeeFromJson(json);
Map<String, dynamic> toJson() => _$EmployeeToJson(this);

} ` 带有@JsonKey的只输出了最后一个,希望可以解决,大佬!!!