Reading error with Diodes in series with resistor

[alexabrev]

I simulated two diodes in series with the cathodes pointed to the positive side of the loop and a resistor connected in sequence. The resulting voltage on the anode side of the resistor should be zero, but it has voltage. Could someone explain to me if I used this simulation in the wrong way or if there is some bug in this type of circuit assembly? Thanks

$ 1 0.000005 10.20027730826997 50 5 50 5e-11 w 1216 0 1392 0 0 w 1392 80 1392 160 2 w 1216 144 1216 528 0 w 1216 528 1392 528 0 r 1392 288 1392 368 0 2050 d 1392 240 1392 160 2 default d 1392 80 1392 0 2 default w 1392 240 1392 288 2 w 1392 368 1392 528 2 v 1216 144 1216 0 0 0 40 12 0 0 0.5 g 1216 528 1136 528 0 0

[pfalstad]

the current through a diode is not zero when it is reversed biased. It is generally equal to the saturation current, which is about 171 nanoamps for the default diode model. 171 nA * 2050 ohms = about 350 microvolts which is why you're seeing that voltage.

[alexabrev]

Between D1 and D2, if I'm not totally wrong, the value should be 0 V, not 6 V as it appears, right?

Thank you very much! Your project is amazing!

[pfalstad]

the current through each diode is the same, so the voltage across each one should be the same. It doesn't make sense for one diode to have 12 V across it and the other one to have 0 V across it. Each diode has about 6 V across it. That's why the voltage is 6V in the middle.

[alexabrev]

Perfect! Thank you!

$ 1 0.000005 10.20027730826997 50 5 50 5e-11 w 1168 0 1344 0 0 w 1344 0 1344 16 2 w 1168 144 1168 528 0 w 1168 528 1344 528 0 r 1344 256 1344 336 0 1000 d 1344 208 1344 128 2 default d 1344 128 1344 16 2 default w 1344 208 1344 256 2 w 1344 336 1344 528 2 v 1168 144 1168 0 0 0 40 12 0 0 0.5 g 1168 528 1088 528 0 0 o 6 64 0 4099 10 0.00009765625 0 2 6 3 o 5 64 0 4099 10 0.00009765625 1 2 5 3