Getting all 0 for cpu.Percent on Centos

[subbu05]

package main

import (
    "fmt"

    "github.com/shirou/gopsutil/cpu"
    "time"
)

func main() {

    percent,_ := cpu.Percent(time.Second,true)
    fmt.Println(percent)
    //fmt.Printf("CPU_Usage(percentage)-User:%.2f Nice:%.2f Sys:%.2f Intr:%.2f Idle:%.2f States:%.2f",percent[0],percent[1],percent[2],percent[3],percent[4],percent[5])
}

Output [0 0 0 0]

cat /etc/redhat-release
CentOS Linux release 7.4.1708 (Core)
[root@5b318c987c94 /]# uname -a
Linux 5b318c987c94 4.9.93-linuxkit-aufs #1 SMP Wed Jun 6 16:55:56 UTC 2018 x86_64 x86_64 x86_64 GNU/Linux

[josueneo]

Have you tried to put some load onto the OS and see some real cpu usage?

[subbu05]

Yes with load I see all 0's Also the array size is 4 instead 5.

[josueneo]

The output is only 1 total usage for each cpu core, which in your case is 4 cores.

I will test tomorrow in a centos vm.

[Lomanic]

Also the array size is 4 instead 5.

How many cores are returned by cpu.Info or cpu.Counts?

[subbu05]

I have mac with 4 core CPU.

[Lomanic]

cpu.Percent gets its data from /proc/stat (via cpu.Times()), can you paste its content here? Thanks in advance.

The number of cores seems right to me by the way.

[Lomanic]

@subbu05 I would appreciate if you could report the result of the following https://github.com/shirou/gopsutil/issues/568#issuecomment-446009859

[Lomanic]

No news from reporter.