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Currently, ByteBuffer always allocates in powers of 2 which makes sense. But many allocators have a small amount of overhead which means the actual space reservation might be even bigger, possibly ano…
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### STOP! ATS 20+ users!
The below isn't needed!
**G8PTN** has pointed out that it HAS the needed resistors already on the A1 pin of the device...
Please follow his advice, and leave your solderi…
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(The included sample textures)
And if you add padding to texture to make it 512x512, image position is wrong..
maybe need to add shader variables for giving sprite height and amount?
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https://csound.com/manual/SiggenTableacc.html
Is this Note no longer true for 7.0?
[Note] Note
Although tables with a size which is not a power of two can be created using a negative size (see [f…
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Hi,
First of all, thank you for your work!
I tried tonight to solder wires to the TX/RX pads, tripped, and ripped off the conductive layer on the TX1 pad; I tried recovering by scraping off a bi…
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"Internal error: 745 shards not a power of 2"
```
➤ TIPPECANOE_MAX_THREADS=256 time tippecanoe -Z9 -z9 -f -o foo.mbtiles tippecanoe/ne_10m_admin_0_countries.json
For layer 0, using name "ne_10m_a…
e-n-f updated
6 months ago
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# Proposal
## Problem statement
[`next_power_of_two`] is implemented for unsigned integers but no corresponding `prev_power_of_two` is available.
Some other common integral bit and power-of-2 o…
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### 问题描述
给你一个整数 n,请你判断该整数是否是 2 的幂次方。如果是,返回 true ;否则,返回 false 。
如果存在一个整数 x 使得 n == 2x ,则认为 n 是 2 的幂次方。
示例 1:
输入:n = 1
输出:true
解释:20 = 1
示例 2:
输入:n = 16
输出:true
解释:24 = 16
示例 3:
输入:n…
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The output power of the inverter can be set via the openDTU with two different parameters: "permanent" (persistent) and "non-permanent" (non-persistent).
There is only one parameter, is it permanent …
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Migrated from [rt.perl.org#42260](https://rt-archive.perl.org/perl5/Ticket/Display.html?id=42260) (status was 'open')
Searchable as RT42260$
p5pRT updated
2 years ago